mirror of git://gcc.gnu.org/git/gcc.git
389 lines
11 KiB
Java
389 lines
11 KiB
Java
// BitSet - A vector of bits.
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/* Copyright (C) 1998, 1999, 2000 Free Software Foundation
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This file is part of GNU Classpath.
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GNU Classpath is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 2, or (at your option)
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any later version.
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GNU Classpath is distributed in the hope that it will be useful, but
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WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with GNU Classpath; see the file COPYING. If not, write to the
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Free Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
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02111-1307 USA.
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As a special exception, if you link this library with other files to
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produce an executable, this library does not by itself cause the
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resulting executable to be covered by the GNU General Public License.
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This exception does not however invalidate any other reasons why the
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executable file might be covered by the GNU General Public License. */
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package java.util;
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import java.io.Serializable;
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/* Written using "Java Class Libraries", 2nd edition, ISBN 0-201-31002-3
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* hashCode algorithm taken from JDK 1.2 docs.
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*/
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/**
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* This class can be thought of in two ways. You can see it as a
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* vector of bits or as a set of non-negative integers. The name
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* <code>BitSet</code> is a bit misleading.
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*
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* It is implemented by a bit vector, but its equally possible to see
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* it as set of non-negative integer; each integer in the set is
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* represented by a set bit at the corresponding index. The size of
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* this structure is determined by the highest integer in the set.
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*
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* You can union, intersect and build (symmetric) remainders, by
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* invoking the logical operations and, or, andNot, resp. xor.
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*
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* This implementation is NOT synchronized against concurrent access from
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* multiple threads. Specifically, if one thread is reading from a bitset
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* while another thread is simultaneously modifying it, the results are
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* undefined.
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*
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* @specnote Historically, there has been some confusion as to whether or not
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* this class should be synchronized. From an efficiency perspective,
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* it is very undesirable to synchronize it because multiple locks
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* and explicit lock ordering are required to safely synchronize some
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* methods. The JCL 1.2 supplement book specifies that as of JDK
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* 1.2, the class is no longer synchronized.
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*
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* @author Jochen Hoenicke
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* @author Tom Tromey <tromey@cygnus.com>
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* @date October 23, 1998.
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* @status API complete to JDK 1.3.
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*/
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public class BitSet implements Cloneable, Serializable
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{
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/**
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* Create a new empty bit set.
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*/
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public BitSet()
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{
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this(64);
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}
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/**
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* Create a new empty bit set, with a given size. This
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* constructor reserves enough space to represent the integers
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* from <code>0</code> to <code>nbits-1</code>.
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* @param nbits the initial size of the bit set.
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* @throws NegativeArraySizeException if the specified initial
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* size is negative.
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* @require nbits >= 0
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*/
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public BitSet(int nbits)
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{
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if (nbits < 0)
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throw new NegativeArraySizeException();
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int length = nbits / 64;
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if (nbits % 64 != 0)
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++length;
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bits = new long[length];
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}
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/**
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* Performs the logical AND operation on this bit set and the
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* given <code>set</code>. This means it builds the intersection
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* of the two sets. The result is stored into this bit set.
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* @param set the second bit set.
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* @require set != null
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*/
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public void and(BitSet bs)
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{
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int max = Math.min(bits.length, bs.bits.length);
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int i;
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for (i = 0; i < max; ++i)
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bits[i] &= bs.bits[i];
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for (; i < bits.length; ++i)
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bits[i] = 0;
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}
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/**
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* Performs the logical AND operation on this bit set and the
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* complement of the given <code>set</code>. This means it
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* selects every element in the first set, that isn't in the
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* second set. The result is stored into this bit set.
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* @param set the second bit set.
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* @require set != null
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* @since JDK1.2
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*/
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public void andNot(BitSet bs)
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{
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int max = Math.min(bits.length, bs.bits.length);
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int i;
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for (i = 0; i < max; ++i)
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bits[i] &= ~bs.bits[i];
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}
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/**
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* Removes the integer <code>bitIndex</code> from this set. That is
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* the corresponding bit is cleared. If the index is not in the set,
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* this method does nothing.
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* @param bitIndex a non-negative integer.
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* @exception ArrayIndexOutOfBoundsException if the specified bit index
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* is negative.
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* @require bitIndex >= 0
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*/
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public void clear(int pos)
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{
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if (pos < 0)
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throw new IndexOutOfBoundsException();
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int bit = pos % 64;
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int offset = pos / 64;
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ensure(offset);
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bits[offset] &= ~(1L << bit);
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}
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/**
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* Create a clone of this bit set, that is an instance of the same
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* class and contains the same elements. But it doesn't change when
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* this bit set changes.
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* @return the clone of this object.
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*/
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public Object clone()
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{
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BitSet bs = new BitSet(bits.length * 64);
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System.arraycopy(bits, 0, bs.bits, 0, bits.length);
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return bs;
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}
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/**
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* Returns true if the <code>obj</code> is a bit set that contains
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* exactly the same elements as this bit set, otherwise false.
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* @return true if obj equals this bit set.
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*/
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public boolean equals(Object obj)
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{
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if (!(obj instanceof BitSet))
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return false;
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BitSet bs = (BitSet) obj;
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int max = Math.min(bits.length, bs.bits.length);
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int i;
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for (i = 0; i < max; ++i)
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if (bits[i] != bs.bits[i])
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return false;
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// If one is larger, check to make sure all extra bits are 0.
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for (int j = i; j < bits.length; ++j)
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if (bits[j] != 0)
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return false;
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for (int j = i; j < bs.bits.length; ++j)
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if (bs.bits[j] != 0)
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return false;
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return true;
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}
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/**
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* Returns true if the integer <code>bitIndex</code> is in this bit
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* set, otherwise false.
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* @param bitIndex a non-negative integer
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* @return the value of the bit at the specified index.
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* @exception ArrayIndexOutOfBoundsException if the specified bit index
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* is negative.
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* @require bitIndex >= 0
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*/
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public boolean get(int pos)
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{
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if (pos < 0)
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throw new IndexOutOfBoundsException();
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int bit = pos % 64;
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int offset = pos / 64;
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if (offset >= bits.length)
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return false;
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return (bits[offset] & (1L << bit)) == 0 ? false : true;
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}
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/**
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* Returns a hash code value for this bit set. The hash code of
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* two bit sets containing the same integers is identical. The algorithm
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* used to compute it is as follows:
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*
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* Suppose the bits in the BitSet were to be stored in an array of
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* long integers called <code>bits</code>, in such a manner that
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* bit <code>k</code> is set in the BitSet (for non-negative values
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* of <code>k</code>) if and only if
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*
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* <pre>
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* ((k/64) < bits.length) && ((bits[k/64] & (1L << (bit % 64))) != 0)
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* </pre>
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*
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* Then the following definition of the hashCode method
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* would be a correct implementation of the actual algorithm:
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*
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* <pre>
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* public int hashCode() {
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* long h = 1234;
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* for (int i = bits.length-1; i>=0; i--) {
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* h ^= bits[i] * (i + 1);
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* }
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* return (int)((h >> 32) ^ h);
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* }
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* </pre>
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*
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* Note that the hash code values changes, if the set is changed.
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* @return the hash code value for this bit set.
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*/
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public int hashCode()
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{
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long h = 1234;
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for (int i = bits.length - 1; i >= 0; --i)
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h ^= bits[i] * (i + 1);
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return (int) ((h >> 32) ^ h);
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}
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/**
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* Returns the logical number of bits actually used by this bit
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* set. It returns the index of the highest set bit plus one.
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* Note that this method doesn't return the number of set bits.
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* @return the index of the highest set bit plus one.
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*/
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public int length()
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{
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// Set i to highest index that contains a non-zero value.
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int i;
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for (i = bits.length - 1; i >= 0 && bits[i] == 0; --i)
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;
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// if i < 0 all bits are cleared.
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if (i < 0)
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return 0;
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// Now determine the exact length.
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long b = bits[i];
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int len = (i + 1) * 64;
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// b >= 0 checks if the highest bit is zero.
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while (b >= 0)
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{
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--len;
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b <<= 1;
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}
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return len;
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}
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/**
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* Performs the logical OR operation on this bit set and the
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* given <code>set</code>. This means it builds the union
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* of the two sets. The result is stored into this bit set, which
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* grows as necessary.
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* @param set the second bit set.
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* @exception OutOfMemoryError if the current set can't grow.
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* @require set != null
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*/
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public void or(BitSet bs)
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{
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ensure(bs.bits.length - 1);
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int i;
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for (i = 0; i < bs.bits.length; ++i)
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bits[i] |= bs.bits[i];
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}
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/**
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* Add the integer <code>bitIndex</code> to this set. That is
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* the corresponding bit is set to true. If the index was already in
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* the set, this method does nothing. The size of this structure
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* is automatically increased as necessary.
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* @param bitIndex a non-negative integer.
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* @exception ArrayIndexOutOfBoundsException if the specified bit index
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* is negative.
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* @require bitIndex >= 0
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*/
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public void set(int pos)
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{
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if (pos < 0)
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throw new IndexOutOfBoundsException();
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int bit = pos % 64;
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int offset = pos / 64;
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ensure(offset);
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bits[offset] |= 1L << bit;
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}
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/**
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* Returns the number of bits actually used by this bit set. Note
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* that this method doesn't return the number of set bits.
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* @returns the number of bits currently used.
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*/
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public int size()
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{
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return bits.length * 64;
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}
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/**
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* Returns the string representation of this bit set. This
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* consists of a comma separated list of the integers in this set
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* surrounded by curly braces. There is a space after each comma.
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* @return the string representation.
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*/
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public String toString()
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{
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String r = "{";
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boolean first = true;
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for (int i = 0; i < bits.length; ++i)
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{
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long bit = 1;
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long word = bits[i];
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if (word == 0)
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continue;
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for (int j = 0; j < 64; ++j)
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{
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if ((word & bit) != 0)
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{
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if (!first)
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r += ", ";
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r += Integer.toString(64 * i + j);
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first = false;
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}
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bit <<= 1;
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}
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}
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return r += "}";
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}
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/**
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* Performs the logical XOR operation on this bit set and the
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* given <code>set</code>. This means it builds the symmetric
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* remainder of the two sets (the elements that are in one set,
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* but not in the other). The result is stored into this bit set,
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* which grows as necessary.
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* @param set the second bit set.
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* @exception OutOfMemoryError if the current set can't grow.
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* @require set != null
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*/
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public void xor(BitSet bs)
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{
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ensure(bs.bits.length - 1);
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int i;
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for (i = 0; i < bs.bits.length; ++i)
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bits[i] ^= bs.bits[i];
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}
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// Make sure the vector is big enough.
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private final void ensure(int lastElt)
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{
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if (lastElt + 1 > bits.length)
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{
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long[] nd = new long[lastElt + 1];
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System.arraycopy(bits, 0, nd, 0, bits.length);
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bits = nd;
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}
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}
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// The actual bits.
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long[] bits;
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private static final long serialVersionUID = 7997698588986878753L;
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}
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