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			560 lines
		
	
	
		
			21 KiB
		
	
	
	
		
			XML
		
	
	
	
| <sect1 id="manual.ext.allocator.bitmap" xreflabel="bitmap_allocator">
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| <?dbhtml filename="bitmap_allocator.html"?>
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|  
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| <sect1info>
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|   <keywordset>
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|     <keyword>
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|       ISO C++
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|     </keyword>
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|     <keyword>
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|       allocator
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|     </keyword>
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|   </keywordset>
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| </sect1info>
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| 
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| <title>bitmap_allocator</title>
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| 
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| <para>
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| </para>
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| 
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| <sect2 id="allocator.bitmap.design">
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| <title>Design</title>
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| 
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|   <para>
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|     As this name suggests, this allocator uses a bit-map to keep track
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|     of the used and unused memory locations for it's book-keeping
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|     purposes.
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|   </para>
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|   <para>
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|     This allocator will make use of 1 single bit to keep track of
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|     whether it has been allocated or not. A bit 1 indicates free,
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|     while 0 indicates allocated. This has been done so that you can
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|     easily check a collection of bits for a free block. This kind of
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|     Bitmapped strategy works best for single object allocations, and
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|     with the STL type parameterized allocators, we do not need to
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|     choose any size for the block which will be represented by a
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|     single bit. This will be the size of the parameter around which
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|     the allocator has been parameterized. Thus, close to optimal
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|     performance will result. Hence, this should be used for node based
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|     containers which call the allocate function with an argument of 1.
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|   </para>
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| 
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|   <para>
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|     The bitmapped allocator's internal pool is exponentially growing.
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|     Meaning that internally, the blocks acquired from the Free List
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|     Store will double every time the bitmapped allocator runs out of
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|     memory.
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|   </para>
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| 
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|   <para>
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|     The macro <literal>__GTHREADS</literal> decides whether to use
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|     Mutex Protection around every allocation/deallocation. The state
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|     of the macro is picked up automatically from the gthr abstraction
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|     layer.
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|   </para>
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| 
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| </sect2>
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| 
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| <sect2 id="allocator.bitmap.impl">
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| <title>Implementation</title>
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| 
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| <sect3 id="bitmap.impl.free_list_store" xreflabel="Free List Store">
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|   <title>Free List Store</title>
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| 
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|   <para>
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|     The Free List Store (referred to as FLS for the remaining part of this
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|     document) is the Global memory pool that is shared by all instances of
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|     the bitmapped allocator instantiated for any type. This maintains a
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|     sorted order of all free memory blocks given back to it by the
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|     bitmapped allocator, and is also responsible for giving memory to the
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|     bitmapped allocator when it asks for more.
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|   </para>
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|   <para>
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|     Internally, there is a Free List threshold which indicates the
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|     Maximum number of free lists that the FLS can hold internally
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|     (cache).  Currently, this value is set at 64. So, if there are
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|     more than 64 free lists coming in, then some of them will be given
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|     back to the OS using operator delete so that at any given time the
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|     Free List's size does not exceed 64 entries. This is done because
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|     a Binary Search is used to locate an entry in a free list when a
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|     request for memory comes along.  Thus, the run-time complexity of
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|     the search would go up given an increasing size, for 64 entries
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|     however, lg(64) == 6 comparisons are enough to locate the correct
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|     free list if it exists.
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|   </para>  
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|   <para>
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|     Suppose the free list size has reached it's threshold, then the
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|     largest block from among those in the list and the new block will
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|     be selected and given back to the OS. This is done because it
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|     reduces external fragmentation, and allows the OS to use the
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|     larger blocks later in an orderly fashion, possibly merging them
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|     later. Also, on some systems, large blocks are obtained via calls
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|     to mmap, so giving them back to free system resources becomes most
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|     important.
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|   </para>
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|   <para>
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|     The function _S_should_i_give decides the policy that determines
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|     whether the current block of memory should be given to the
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|     allocator for the request that it has made. That's because we may
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|     not always have exact fits for the memory size that the allocator
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|     requests. We do this mainly to prevent external fragmentation at
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|     the cost of a little internal fragmentation. Now, the value of
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|     this internal fragmentation has to be decided by this function. I
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|     can see 3 possibilities right now. Please add more as and when you
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|     find better strategies.
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|   </para>
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| 
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| <orderedlist>
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|   <listitem><para>Equal size check. Return true only when the 2 blocks are of equal
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| size.</para></listitem>
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|   <listitem><para>Difference Threshold: Return true only when the _block_size is
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| greater than or equal to the _required_size, and if the _BS is > _RS
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| by a difference of less than some THRESHOLD value, then return true,
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| else return false. </para></listitem>
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|   <listitem><para>Percentage Threshold. Return true only when the _block_size is
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| greater than or equal to the _required_size, and if the _BS is > _RS
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| by a percentage of less than some THRESHOLD value, then return true,
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| else return false.</para></listitem>
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| </orderedlist>
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| 
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|   <para>
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|     Currently, (3) is being used with a value of 36% Maximum wastage per
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|     Super Block.
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|   </para>
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.super_block" xreflabel="Super Block">
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|   <title>Super Block</title>
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| 
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|   <para>
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|     A super block is the block of memory acquired from the FLS from
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|     which the bitmap allocator carves out memory for single objects
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|     and satisfies the user's requests. These super blocks come in
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|     sizes that are powers of 2 and multiples of 32
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|     (_Bits_Per_Block). Yes both at the same time!  That's because the
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|     next super block acquired will be 2 times the previous one, and
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|     also all super blocks have to be multiples of the _Bits_Per_Block
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|     value.
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|   </para>
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|   <para>
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|     How does it interact with the free list store?
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|   </para>
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|   <para>
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|     The super block is contained in the FLS, and the FLS is responsible for
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|     getting / returning Super Bocks to and from the OS using operator new
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|     as defined by the C++ standard.
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|   </para>
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.super_block_data" xreflabel="Super Block Data">
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|   <title>Super Block Data Layout</title>
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|   <para>
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|     Each Super Block will be of some size that is a multiple of the
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|     number of Bits Per Block. Typically, this value is chosen as
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|     Bits_Per_Byte x sizeof(size_t). On an x86 system, this gives the
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|     figure 8 x 4 = 32. Thus, each Super Block will be of size 32
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|     x Some_Value. This Some_Value is sizeof(value_type). For now, let
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|     it be called 'K'. Thus, finally, Super Block size is 32 x K bytes.
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|   </para>
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|   <para>
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|     This value of 32 has been chosen because each size_t has 32-bits
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|     and Maximum use of these can be made with such a figure.
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|   </para>
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|   <para>
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|     Consider a block of size 64 ints. In memory, it would look like this:
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|     (assume a 32-bit system where, size_t is a 32-bit entity).
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|   </para>
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| 
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| <table frame='all'>
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| <title>Bitmap Allocator Memory Map</title>
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| <tgroup cols='5' align='left' colsep='1' rowsep='1'>
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| <colspec colname='c1'></colspec>
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| <colspec colname='c2'></colspec>
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| <colspec colname='c3'></colspec>
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| <colspec colname='c4'></colspec>
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| <colspec colname='c5'></colspec>
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| 
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| <tbody>
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|   <row>
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|     <entry>268</entry>
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|     <entry>0</entry>
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|     <entry>4294967295</entry>
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|     <entry>4294967295</entry>
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|     <entry>Data -> Space for 64 ints</entry>
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|   </row>
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| </tbody>
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| </tgroup>
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| </table>
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| 
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|   <para>
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|     The first Column(268) represents the size of the Block in bytes as
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|     seen by the Bitmap Allocator. Internally, a global free list is
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|     used to keep track of the free blocks used and given back by the
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|     bitmap allocator.  It is this Free List Store that is responsible
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|     for writing and managing this information. Actually the number of
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|     bytes allocated in this case would be: 4 + 4 + (4x2) + (64x4) =
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|     272 bytes, but the first 4 bytes are an addition by the Free List
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|     Store, so the Bitmap Allocator sees only 268 bytes. These first 4
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|     bytes about which the bitmapped allocator is not aware hold the
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|     value 268.
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|   </para>
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| 
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|   <para>
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|   What do the remaining values represent?</para>
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|   <para>
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|     The 2nd 4 in the expression is the sizeof(size_t) because the
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|     Bitmapped Allocator maintains a used count for each Super Block,
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|     which is initially set to 0 (as indicated in the diagram). This is
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|     incremented every time a block is removed from this super block
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|     (allocated), and decremented whenever it is given back. So, when
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|     the used count falls to 0, the whole super block will be given
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|     back to the Free List Store.
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|   </para>
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|   <para>
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|     The value 4294967295 represents the integer corresponding to the bit
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|     representation of all bits set: 11111111111111111111111111111111.
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|   </para>
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|   <para>
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|     The 3rd 4x2 is size of the bitmap itself, which is the size of 32-bits
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|     x 2,
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|     which is 8-bytes, or 2 x sizeof(size_t).
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|   </para>
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.max_wasted" xreflabel="Max Wasted Percentage">
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|   <title>Maximum Wasted Percentage</title>
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|  
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|   <para>
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|     This has nothing to do with the algorithm per-se,
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|     only with some vales that must be chosen correctly to ensure that the
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|     allocator performs well in a real word scenario, and maintains a good
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|     balance between the memory consumption and the allocation/deallocation
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|     speed.
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|   </para>
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|   <para>
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|     The formula for calculating the maximum wastage as a percentage:
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|   </para>
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| 
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|   <para>
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| (32 x k + 1) / (2 x (32 x k + 1 + 32 x c)) x 100.
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|   </para>
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| 
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|   <para>
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|     where k is the constant overhead per node (e.g., for list, it is
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|     8 bytes, and for map it is 12 bytes) and c is the size of the
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|     base type on which the map/list is instantiated. Thus, suppose the
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|     type1 is int and type2 is double, they are related by the relation
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|     sizeof(double) == 2*sizeof(int). Thus, all types must have this
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|     double size relation for this formula to work properly.
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|   </para>
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|   <para>
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|     Plugging-in: For List: k = 8 and c = 4 (int and double), we get:
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|     33.376%
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|   </para>
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| 
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|   <para>
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| For map/multimap: k = 12, and c = 4 (int and double), we get: 37.524%
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|   </para>
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|   <para>
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|     Thus, knowing these values, and based on the sizeof(value_type), we may
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|     create a function that returns the Max_Wastage_Percentage for us to use.
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|   </para>
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| 
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.allocate" xreflabel="Allocate">
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|   <title><function>allocate</function></title>
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| 
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|   <para>
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|     The allocate function is specialized for single object allocation
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|     ONLY.  Thus, ONLY if n == 1, will the bitmap_allocator's
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|     specialized algorithm be used. Otherwise, the request is satisfied
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|     directly by calling operator new.
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|   </para>
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|   <para>
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|     Suppose n == 1, then the allocator does the following:
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|   </para>
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|   <orderedlist>
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|     <listitem>
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|       <para>
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| 	Checks to see whether a free block exists somewhere in a region
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| 	of memory close to the last satisfied request. If so, then that
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| 	block is marked as allocated in the bit map and given to the
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| 	user. If not, then (2) is executed.
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|     </para>
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|     </listitem>
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|     <listitem>
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|       <para>
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| 	Is there a free block anywhere after the current block right
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| 	up to the end of the memory that we have? If so, that block is
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| 	found, and the same procedure is applied as above, and
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| 	returned to the user. If not, then (3) is executed.
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|     </para>
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|     </listitem>
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|     <listitem>
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|       <para>
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| 	Is there any block in whatever region of memory that we own
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| 	free?  This is done by checking
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|       </para>
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|       <itemizedlist>
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| 	<listitem>
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| 	<para>
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| 	The use count for each super block, and if that fails then
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| 	</para>
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| 	</listitem>
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| 	<listitem>
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| 	<para>
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| 	  The individual bit-maps for each super block.
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| 	</para>
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| 	</listitem>
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|       </itemizedlist>
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| 
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|       <para>
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| 	Note: Here we are never touching any of the memory that the
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| 	user will be given, and we are confining all memory accesses
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| 	to a small region of memory! This helps reduce cache
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| 	misses. If this succeeds then we apply the same procedure on
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| 	that bit-map as (1), and return that block of memory to the
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| 	user. However, if this process fails, then we resort to (4).
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| 	</para>
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|     </listitem>
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|     <listitem>
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|       <para>
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| 	This process involves Refilling the internal exponentially
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| 	growing memory pool. The said effect is achieved by calling
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| 	_S_refill_pool which does the following:
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|       </para>
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|       <itemizedlist>
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| 	<listitem>
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| 	  <para>
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| 	    Gets more memory from the Global Free List of the Required
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| 	    size.  
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| 	  </para>
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| 	</listitem>
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|       <listitem>
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|       <para>
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|       Adjusts the size for the next call to itself. 
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|       </para>
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|       </listitem>
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|       <listitem>
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|       <para>
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|       Writes the appropriate headers in the bit-maps.
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|       </para>
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|       </listitem>
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|       <listitem>
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| 	<para>
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| 	Sets the use count for that super-block just allocated to 0
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| 	(zero).  
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|       </para>
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|       </listitem>
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|       <listitem>
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| 	<para>
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| 	  All of the above accounts to maintaining the basic invariant
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| 	  for the allocator. If the invariant is maintained, we are
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| 	  sure that all is well. Now, the same process is applied on
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| 	  the newly acquired free blocks, which are dispatched
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| 	  accordingly.  
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|       </para>
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|       </listitem>
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|     </itemizedlist>
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|     </listitem>
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| </orderedlist>
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| 
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| <para>
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| Thus, you can clearly see that the allocate function is nothing but a
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| combination of the next-fit and first-fit algorithm optimized ONLY for
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| single object allocations.
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| </para>
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| 
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.deallocate" xreflabel="Deallocate">
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|   <title><function>deallocate</function></title>
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|   <para>
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|     The deallocate function again is specialized for single objects ONLY.
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|     For all n belonging to > 1, the operator delete is called without
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|     further ado, and the deallocate function returns.
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|   </para>
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|   <para>
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|     However for n == 1, a series of steps are performed:
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|   </para>
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|   
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|   <orderedlist>
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|     <listitem><para>
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|       We first need to locate that super-block which holds the memory
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|       location given to us by the user. For that purpose, we maintain
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|       a static variable _S_last_dealloc_index, which holds the index
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|       into the vector of block pairs which indicates the index of the
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|       last super-block from which memory was freed. We use this
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|       strategy in the hope that the user will deallocate memory in a
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|       region close to what he/she deallocated the last time around. If
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|       the check for belongs_to succeeds, then we determine the bit-map
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|       for the given pointer, and locate the index into that bit-map,
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|       and mark that bit as free by setting it.
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|     </para></listitem>
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|     <listitem><para>
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|       If the _S_last_dealloc_index does not point to the memory block
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|       that we're looking for, then we do a linear search on the block
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|       stored in the vector of Block Pairs. This vector in code is
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|       called _S_mem_blocks. When the corresponding super-block is
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|       found, we apply the same procedure as we did for (1) to mark the
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|       block as free in the bit-map.
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|     </para></listitem>
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|   </orderedlist>
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| 
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|   <para>
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|     Now, whenever a block is freed, the use count of that particular
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|     super block goes down by 1. When this use count hits 0, we remove
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|     that super block from the list of all valid super blocks stored in
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|     the vector.  While doing this, we also make sure that the basic
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|     invariant is maintained by making sure that _S_last_request and
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|     _S_last_dealloc_index point to valid locations within the vector.
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|   </para>
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| </sect3>
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| 
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| <sect3 id="bitmap.impl.questions" xreflabel="Questions">
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|   <title>Questions</title>
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| 
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|   <sect4 id="bitmap.impl.question.1" xreflabel="Question 1">
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|     <title>1</title>
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|     <para>
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| Q1) The "Data Layout" section is
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| cryptic. I have no idea of what you are trying to say. Layout of what?
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| The free-list? Each bitmap? The Super Block?
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|     </para>
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|     <para>
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|       The layout of a Super Block of a given
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| size. In the example, a super block of size 32 x 1 is taken. The
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| general formula for calculating the size of a super block is
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| 32 x sizeof(value_type) x 2^n, where n ranges from 0 to 32 for 32-bit
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| systems.
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|     </para>
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|   </sect4>
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| 
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|   <sect4 id="bitmap.impl.question.2" xreflabel="Question 2">
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|     <title>2</title>
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|     <para>
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|       And since I just mentioned the
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| term `each bitmap', what in the world is meant by it? What does each
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| bitmap manage? How does it relate to the super block? Is the Super
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| Block a bitmap as well?
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|     </para>
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|     <para>
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|       Each bitmap is part of a Super Block which is made up of 3 parts
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|       as I have mentioned earlier.  Re-iterating, 1. The use count,
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|       2. The bit-map for that Super Block. 3.  The actual memory that
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|       will be eventually given to the user. Each bitmap is a multiple
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|       of 32 in size. If there are 32 x (2^3) blocks of single objects
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|       to be given, there will be '32 x (2^3)' bits present.  Each 32
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|       bits managing the allocated / free status for 32 blocks. Since
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|       each size_t contains 32-bits, one size_t can manage up to 32
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|       blocks' status. Each bit-map is made up of a number of size_t,
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|       whose exact number for a super-block of a given size I have just
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|       mentioned.
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|     </para>
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|   </sect4>
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| 
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|   <sect4 id="bitmap.impl.question.3" xreflabel="Question 3">
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|     <title>3</title>
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|     <para>
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|       How do the allocate and deallocate functions work in regard to
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|       bitmaps?
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|     </para>
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|     <para>
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|       The allocate and deallocate functions manipulate the bitmaps and
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|       have nothing to do with the memory that is given to the user. As
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|       I have earlier mentioned, a 1 in the bitmap's bit field
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|       indicates free, while a 0 indicates allocated. This lets us
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|       check 32 bits at a time to check whether there is at lease one
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|       free block in those 32 blocks by testing for equality with
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|       (0). Now, the allocate function will given a memory block find
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|       the corresponding bit in the bitmap, and will reset it (i.e.,
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|       make it re-set (0)). And when the deallocate function is called,
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|       it will again set that bit after locating it to indicate that
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|       that particular block corresponding to this bit in the bit-map
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|       is not being used by anyone, and may be used to satisfy future
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|       requests.
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|     </para>
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|     <para>
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|       e.g.: Consider a bit-map of 64-bits as represented below:
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|       1111111111111111111111111111111111111111111111111111111111111111
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|     </para>
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| 
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|     <para>
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|       Now, when the first request for allocation of a single object
 | |
|       comes along, the first block in address order is returned. And
 | |
|       since the bit-maps in the reverse order to that of the address
 | |
|       order, the last bit (LSB if the bit-map is considered as a
 | |
|       binary word of 64-bits) is re-set to 0.
 | |
|     </para>
 | |
| 
 | |
|     <para>
 | |
|       The bit-map now looks like this:
 | |
|       1111111111111111111111111111111111111111111111111111111111111110
 | |
|     </para>
 | |
|   </sect4>
 | |
| </sect3>
 | |
| 
 | |
| <sect3 id="bitmap.impl.locality" xreflabel="Locality">
 | |
|   <title>Locality</title>
 | |
|   <para>
 | |
|     Another issue would be whether to keep the all bitmaps in a
 | |
|     separate area in memory, or to keep them near the actual blocks
 | |
|     that will be given out or allocated for the client. After some
 | |
|     testing, I've decided to keep these bitmaps close to the actual
 | |
|     blocks. This will help in 2 ways.
 | |
|   </para>
 | |
|   
 | |
|   <orderedlist>
 | |
|   <listitem><para>Constant time access for the bitmap themselves, since no kind of
 | |
| look up will be needed to find the correct bitmap list or it's
 | |
| equivalent.</para></listitem>
 | |
|   <listitem><para>And also this would preserve the cache as far as possible.</para></listitem>
 | |
|   </orderedlist>
 | |
| 
 | |
|   <para>
 | |
|     So in effect, this kind of an allocator might prove beneficial from a
 | |
|     purely cache point of view. But this allocator has been made to try and
 | |
|     roll out the defects of the node_allocator, wherein the nodes get
 | |
|     skewed about in memory, if they are not returned in the exact reverse
 | |
|     order or in the same order in which they were allocated. Also, the
 | |
|     new_allocator's book keeping overhead is too much for small objects and
 | |
|     single object allocations, though it preserves the locality of blocks
 | |
|     very well when they are returned back to the allocator.
 | |
|   </para>
 | |
| </sect3>
 | |
| 
 | |
| <sect3 id="bitmap.impl.grow_policy" xreflabel="Grow Policy">
 | |
|   <title>Overhead and Grow Policy</title>
 | |
|   <para>
 | |
|     Expected overhead per block would be 1 bit in memory. Also, once
 | |
|     the address of the free list has been found, the cost for
 | |
|     allocation/deallocation would be negligible, and is supposed to be
 | |
|     constant time. For these very reasons, it is very important to
 | |
|     minimize the linear time costs, which include finding a free list
 | |
|     with a free block while allocating, and finding the corresponding
 | |
|     free list for a block while deallocating. Therefore, I have
 | |
|     decided that the growth of the internal pool for this allocator
 | |
|     will be exponential as compared to linear for
 | |
|     node_allocator. There, linear time works well, because we are
 | |
|     mainly concerned with speed of allocation/deallocation and memory
 | |
|     consumption, whereas here, the allocation/deallocation part does
 | |
|     have some linear/logarithmic complexity components in it. Thus, to
 | |
|     try and minimize them would be a good thing to do at the cost of a
 | |
|     little bit of memory.
 | |
|   </para>
 | |
| 
 | |
|   <para>
 | |
|     Another thing to be noted is the pool size will double every time
 | |
|     the internal pool gets exhausted, and all the free blocks have
 | |
|     been given away. The initial size of the pool would be
 | |
|     sizeof(size_t) x 8 which is the number of bits in an integer,
 | |
|     which can fit exactly in a CPU register. Hence, the term given is
 | |
|     exponential growth of the internal pool.
 | |
|   </para>
 | |
| </sect3>
 | |
| 
 | |
| </sect2>
 | |
|  
 | |
| </sect1>
 |