kconfig: use hash table to reuse expressions

Currently, every expression in Kconfig files produces a new abstract
syntax tree (AST), even if it is identical to a previously encountered
one.

Consider the following code:

    config FOO
           bool "FOO"
           depends on (A || B) && C

    config BAR
           bool "BAR"
           depends on (A || B) && C

    config BAZ
           bool "BAZ"
           depends on A || B

The "depends on" lines are similar, but currently a separate AST is
allocated for each one.

The current data structure looks like this:

  FOO->dep ==> AND        BAR->dep ==> AND        BAZ->dep ==> OR
              /   \                   /   \                   /  \
            OR     C                OR     C                 A    B
           /  \                    /  \
          A    B                  A    B

This is redundant; FOO->dep and BAR->dep have identical ASTs but
different memory instances.

We can optimize this; FOO->dep and BAR->dep can share the same AST, and
BAZ->dep can reference its sub tree.

The optimized data structure looks like this:

  FOO->dep, BAR->dep ==> AND
                        /   \
         BAZ->dep ==> OR     C
                     /  \
                    A    B

This commit introduces a hash table to keep track of allocated
expressions. If an identical expression is found, it is reused.

This does not necessarily result in memory savings, as menu_finalize()
transforms expressions without freeing up stale ones. This will be
addressed later.

One optimization that can be easily implemented is caching the
expression's value. Once FOO's dependency, (A || B) && C, is calculated,
it can be cached, eliminating the need to recalculate it for BAR.

This commit also reverts commit e983b7b17a ("kconfig/menu.c: fix
multiple references to expressions in menu_add_prop()").

Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>

scripts/kconfig/expr.h

@@ -29,11 +29,21 @@ enum expr_type {
 };
 
 union expr_data {
-	struct expr *expr;
-	struct symbol *sym;
+	struct expr * const expr;
+	struct symbol * const sym;
+	void *_initdata;
 };
 
+/**
+ * struct expr - expression
+ *
+ * @node:  link node for the hash table
+ * @type:  expressoin type
+ * @left:  left node
+ * @right: right node
+ */
 struct expr {
+	struct hlist_node node;
 	enum expr_type type;
 	union expr_data left, right;
 };
@@ -275,8 +285,6 @@ struct expr *expr_alloc_two(enum expr_type type, struct expr *e1, struct expr *e
 struct expr *expr_alloc_comp(enum expr_type type, struct symbol *s1, struct symbol *s2);
 struct expr *expr_alloc_and(struct expr *e1, struct expr *e2);
 struct expr *expr_alloc_or(struct expr *e1, struct expr *e2);
-struct expr *expr_copy(const struct expr *org);
-void expr_free(struct expr *e);
 void expr_eliminate_eq(struct expr **ep1, struct expr **ep2);
 bool expr_eq(struct expr *e1, struct expr *e2);
 tristate expr_calc_value(struct expr *e);