nstree: make struct ns_tree private
Don't expose it directly. There's no need to do that. Reviewed-by: Jan Kara <jack@suse.cz> Signed-off-by: Christian Brauner <brauner@kernel.org>
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@ -9,19 +9,6 @@
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#include <linux/rculist.h>
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#include <linux/rculist.h>
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#include <linux/cookie.h>
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#include <linux/cookie.h>
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/**
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* struct ns_tree - Namespace tree
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* @ns_tree: Rbtree of namespaces of a particular type
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* @ns_list: Sequentially walkable list of all namespaces of this type
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* @ns_tree_lock: Seqlock to protect the tree and list
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*/
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struct ns_tree {
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struct rb_root ns_tree;
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struct list_head ns_list;
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seqlock_t ns_tree_lock;
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int type;
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};
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extern struct ns_tree cgroup_ns_tree;
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extern struct ns_tree cgroup_ns_tree;
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extern struct ns_tree ipc_ns_tree;
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extern struct ns_tree ipc_ns_tree;
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extern struct ns_tree mnt_ns_tree;
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extern struct ns_tree mnt_ns_tree;
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@ -4,6 +4,20 @@
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#include <linux/proc_ns.h>
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#include <linux/proc_ns.h>
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#include <linux/vfsdebug.h>
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#include <linux/vfsdebug.h>
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/**
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* struct ns_tree - Namespace tree
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* @ns_tree: Rbtree of namespaces of a particular type
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* @ns_list: Sequentially walkable list of all namespaces of this type
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* @ns_tree_lock: Seqlock to protect the tree and list
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* @type: type of namespaces in this tree
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*/
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struct ns_tree {
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struct rb_root ns_tree;
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struct list_head ns_list;
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seqlock_t ns_tree_lock;
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int type;
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};
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struct ns_tree mnt_ns_tree = {
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struct ns_tree mnt_ns_tree = {
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.ns_tree = RB_ROOT,
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.ns_tree = RB_ROOT,
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.ns_list = LIST_HEAD_INIT(mnt_ns_tree.ns_list),
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.ns_list = LIST_HEAD_INIT(mnt_ns_tree.ns_list),
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